# The substitution and factoring methods to solve limit:

0 The substitution and the factoring methods are the most utilized methods in solving the limit. We need to learn there are two types of the limit, the finite and the infinite limit and we utilize the substitution and factoring methods to solve those limits. The limit calculator makes it clear to us how to implement the substitution and the factoring methods. Normally when you are dealing with the quadratic function, we normally factorize the fractions. On the other hand, the substitution method is utilized directly to solve the limit.

You may be thinking, about how to find limits and how to implement the limit on the algebraic function. The limit calculator with steps makes the task easy for us and we can solve the limit in steps without any difficulty. The aim calculator makes the task easy for the students and you can solve the limit. The concept of the limit is frequently encountered by the students when they are solving derivation or integration.

Here in this topic, we are going to learn the concepts of substitution and factoring to solve the limit.

The Substitution methods:

The substitution method is used to solve the limit directly by the limit solver. When you are going to solve the limit by the limit calculator, then you are directly able to implement the limit in an algebraic function.

We are going to examine the Substitution limit by implementing it in various functions:

f(x)x5x2-4x+25x-4

We are going to implement the f(x)x5 in the algebraic function x2-4x+25x-4

f(x)(5)2-4(5)+255-4

Add the limit of the function:

f(x)25-20+255-4

f(x)301

f(x)=  30

Consider another example, where there is a quadratic function in both the denominator and numerator places. Then by utilizing the limit calculator, we can solve the substitution as follows:

f(x)x5x2-4x+25x2-x+20

We are going to implement the f(x)x5 in the algebraic function x2-4x+25x2-x+20

f(x)(5)2-4(5)+25(5)2-5+20

Add the limit of the function:

f(x)(5)2-4(5)+25(5)2-5+20

f(x)25-4(5)+2525-5+20

f(x)25-20+2525-5+20

f(x)25-20+2525-5+20

f(x)=50-2045-5

f(x)=3040

f(x)=3/4

The limit calculator makes the concept of the limit by the sunsiti0n process easy and fast.

## In the limit calculator with steps, we do implement the limit on another function.

f(x)x3x2-6x+9x-3

f(x)x3x2-3x-3x+9x-3

f(x)x3x(x-3)-3(x-5)x-3

f(x)x5(x-3)(x-3)x-3

Cut down the (x-3), on both the denominator and the numerator, and the remaining term as:

f(x)x3(x-3)

f(x)(3-3)

The answer is “0” of the function f(x)x3x2-6x+9x-3

f(x)0

Conclusion:

The limit calculator helps to find the limit by the substitution and the factoring method. We can implement the factoring method on algebraic functions where substitution can’t be able to find the solution to the question. We can’t escape the basic concepts of Math when solving the simple question of Math. The online tools and apps make the task just too simple for the students and for the learners.